Integrand size = 23, antiderivative size = 76 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=-\frac {(a-b) \sqrt {b} \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {(a-b) \cot (e+f x)}{a^2 f}-\frac {\cot ^3(e+f x)}{3 a f} \]
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Time = 0.12 (sec) , antiderivative size = 76, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {3744, 464, 331, 211} \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=-\frac {\sqrt {b} (a-b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {(a-b) \cot (e+f x)}{a^2 f}-\frac {\cot ^3(e+f x)}{3 a f} \]
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Rule 211
Rule 331
Rule 464
Rule 3744
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1+x^2}{x^4 \left (a+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{f} \\ & = -\frac {\cot ^3(e+f x)}{3 a f}+\frac {(a-b) \text {Subst}\left (\int \frac {1}{x^2 \left (a+b x^2\right )} \, dx,x,\tan (e+f x)\right )}{a f} \\ & = -\frac {(a-b) \cot (e+f x)}{a^2 f}-\frac {\cot ^3(e+f x)}{3 a f}-\frac {((a-b) b) \text {Subst}\left (\int \frac {1}{a+b x^2} \, dx,x,\tan (e+f x)\right )}{a^2 f} \\ & = -\frac {(a-b) \sqrt {b} \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a}}\right )}{a^{5/2} f}-\frac {(a-b) \cot (e+f x)}{a^2 f}-\frac {\cot ^3(e+f x)}{3 a f} \\ \end{align*}
Time = 0.65 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.96 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=\frac {3 \sqrt {b} (-a+b) \arctan \left (\frac {\sqrt {b} \tan (e+f x)}{\sqrt {a}}\right )-\sqrt {a} \cot (e+f x) \left (2 a-3 b+a \csc ^2(e+f x)\right )}{3 a^{5/2} f} \]
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Time = 0.43 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.88
method | result | size |
derivativedivides | \(\frac {-\frac {1}{3 a \tan \left (f x +e \right )^{3}}-\frac {a -b}{a^{2} \tan \left (f x +e \right )}-\frac {b \left (a -b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {a b}}\right )}{a^{2} \sqrt {a b}}}{f}\) | \(67\) |
default | \(\frac {-\frac {1}{3 a \tan \left (f x +e \right )^{3}}-\frac {a -b}{a^{2} \tan \left (f x +e \right )}-\frac {b \left (a -b \right ) \arctan \left (\frac {b \tan \left (f x +e \right )}{\sqrt {a b}}\right )}{a^{2} \sqrt {a b}}}{f}\) | \(67\) |
risch | \(\frac {2 i \left (3 b \,{\mathrm e}^{4 i \left (f x +e \right )}+6 a \,{\mathrm e}^{2 i \left (f x +e \right )}-6 b \,{\mathrm e}^{2 i \left (f x +e \right )}-2 a +3 b \right )}{3 f \,a^{2} \left ({\mathrm e}^{2 i \left (f x +e \right )}-1\right )^{3}}+\frac {\sqrt {-a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-a b}+a +b}{a -b}\right )}{2 a^{2} f}-\frac {\sqrt {-a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}+\frac {2 i \sqrt {-a b}+a +b}{a -b}\right ) b}{2 a^{3} f}-\frac {\sqrt {-a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-a b}-a -b}{a -b}\right )}{2 a^{2} f}+\frac {\sqrt {-a b}\, \ln \left ({\mathrm e}^{2 i \left (f x +e \right )}-\frac {2 i \sqrt {-a b}-a -b}{a -b}\right ) b}{2 a^{3} f}\) | \(259\) |
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Leaf count of result is larger than twice the leaf count of optimal. 142 vs. \(2 (66) = 132\).
Time = 0.30 (sec) , antiderivative size = 373, normalized size of antiderivative = 4.91 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=\left [-\frac {4 \, {\left (2 \, a - 3 \, b\right )} \cos \left (f x + e\right )^{3} + 3 \, {\left ({\left (a - b\right )} \cos \left (f x + e\right )^{2} - a + b\right )} \sqrt {-\frac {b}{a}} \log \left (\frac {{\left (a^{2} + 6 \, a b + b^{2}\right )} \cos \left (f x + e\right )^{4} - 2 \, {\left (3 \, a b + b^{2}\right )} \cos \left (f x + e\right )^{2} - 4 \, {\left ({\left (a^{2} + a b\right )} \cos \left (f x + e\right )^{3} - a b \cos \left (f x + e\right )\right )} \sqrt {-\frac {b}{a}} \sin \left (f x + e\right ) + b^{2}}{{\left (a^{2} - 2 \, a b + b^{2}\right )} \cos \left (f x + e\right )^{4} + 2 \, {\left (a b - b^{2}\right )} \cos \left (f x + e\right )^{2} + b^{2}}\right ) \sin \left (f x + e\right ) - 12 \, {\left (a - b\right )} \cos \left (f x + e\right )}{12 \, {\left (a^{2} f \cos \left (f x + e\right )^{2} - a^{2} f\right )} \sin \left (f x + e\right )}, -\frac {2 \, {\left (2 \, a - 3 \, b\right )} \cos \left (f x + e\right )^{3} - 3 \, {\left ({\left (a - b\right )} \cos \left (f x + e\right )^{2} - a + b\right )} \sqrt {\frac {b}{a}} \arctan \left (\frac {{\left ({\left (a + b\right )} \cos \left (f x + e\right )^{2} - b\right )} \sqrt {\frac {b}{a}}}{2 \, b \cos \left (f x + e\right ) \sin \left (f x + e\right )}\right ) \sin \left (f x + e\right ) - 6 \, {\left (a - b\right )} \cos \left (f x + e\right )}{6 \, {\left (a^{2} f \cos \left (f x + e\right )^{2} - a^{2} f\right )} \sin \left (f x + e\right )}\right ] \]
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\[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=\int \frac {\csc ^{4}{\left (e + f x \right )}}{a + b \tan ^{2}{\left (e + f x \right )}}\, dx \]
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Time = 0.30 (sec) , antiderivative size = 68, normalized size of antiderivative = 0.89 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=-\frac {\frac {3 \, {\left (a b - b^{2}\right )} \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b}}\right )}{\sqrt {a b} a^{2}} + \frac {3 \, {\left (a - b\right )} \tan \left (f x + e\right )^{2} + a}{a^{2} \tan \left (f x + e\right )^{3}}}{3 \, f} \]
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Time = 0.48 (sec) , antiderivative size = 92, normalized size of antiderivative = 1.21 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=-\frac {\frac {3 \, {\left (\pi \left \lfloor \frac {f x + e}{\pi } + \frac {1}{2} \right \rfloor \mathrm {sgn}\left (b\right ) + \arctan \left (\frac {b \tan \left (f x + e\right )}{\sqrt {a b}}\right )\right )} {\left (a b - b^{2}\right )}}{\sqrt {a b} a^{2}} + \frac {3 \, a \tan \left (f x + e\right )^{2} - 3 \, b \tan \left (f x + e\right )^{2} + a}{a^{2} \tan \left (f x + e\right )^{3}}}{3 \, f} \]
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Time = 10.07 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.88 \[ \int \frac {\csc ^4(e+f x)}{a+b \tan ^2(e+f x)} \, dx=-\frac {\frac {1}{3\,a}+\frac {{\mathrm {tan}\left (e+f\,x\right )}^2\,\left (a-b\right )}{a^2}}{f\,{\mathrm {tan}\left (e+f\,x\right )}^3}-\frac {\sqrt {b}\,\mathrm {atan}\left (\frac {\sqrt {b}\,\mathrm {tan}\left (e+f\,x\right )}{\sqrt {a}}\right )\,\left (a-b\right )}{a^{5/2}\,f} \]
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